Answer:
Distance between nina's house to her friend's home = AC = 5 miles
Explanation:
Distance between nina's house to her school = BC = 4 miles
Distance between nina's school to her friend's home = BA = 3 miles
Distance between nina's house to her friend's home = AC = ??
From the ΔABC
![AC^(2) = AB^(2) + BC^(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/jq0bjznw6lxk7ea47ehtmpy2bvdv9rsg8b.png)
![AC^(2) = 3^(2) + 4^(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/n72l8ftyv5vkhgzbhcorm0y2vwzkuqz12z.png)
![AC^(2) =25](https://img.qammunity.org/2021/formulas/mathematics/high-school/zvwa4skohai0rehkwtr3q8eu9ttavjdpka.png)
AC = 5 miles
Therefore Distance between nina's house to her friend's home = AC = 5 miles