Question

The molar solubility of zns is 1.6 Ã 10-12 m in pure water. Calculate the ksp for zns.

Answer 1

The solubility product of zinc sulfide is
`2.56* 10^(-24)`.

Step-by-step explanation:

Solubility of the zinc sulfide =
`S=1.6* 10^(-12)`

`ZnS\rightleftharpoons Zn^(2+)+S^(2-)`

S S

The expression of solubility product is given by :

`K_(sp)=[Zn^(2+)]* [S^(2-)]`

`K_(sp)=S* S=S^2`

`=1.6* 10^(-12)* 1.6* 10^(-12)=2.56* 10^(-24)`

The solubility product of zinc sulfide is
`2.56* 10^(-24)`.