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The molar solubility of zns is 1.6 Ã 10-12 m in pure water. Calculate the ksp for zns.

User Profpatsch
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1 Answer

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Answer:

The solubility product of zinc sulfide is
2.56* 10^(-24).

Step-by-step explanation:

Solubility of the zinc sulfide =
S=1.6* 10^(-12)


ZnS\rightleftharpoons Zn^(2+)+S^(2-)

S S

The expression of solubility product is given by :


K_(sp)=[Zn^(2+)]* [S^(2-)]


K_(sp)=S* S=S^2


=1.6* 10^(-12)* 1.6* 10^(-12)=2.56* 10^(-24)

The solubility product of zinc sulfide is
2.56* 10^(-24).

User Lemieuxster
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