If a bullet of mass 50 gm is moving with the velocity of 720 km/hr. Calculate its kinetic energy. Ans: here, mass (m)= 50 gm = 50/1000 kg = 0.05 kg velocity (v) = 720 km/hr= 720×1000/60×60=200m/s kinetic

If a bullet of mass 50 gm is moving with the velocity of 720 km/hr. Calculate its kinetic energy. Ans: here, mass (m)= 50 gm = 50/1000 kg = 0.05 kg velocity (v) = 720 km/hr= 720×1000/60×60=200m/s kinetic energy = ? We know, K.E.= 1/2 mv^2 = 1/2 × 0.05×(200)^2 = 0.05×40000/2 = 1000j ans. Is it correct???????

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