Answer:
The probability of getting an odd number when the spinner is spun, is p(even number) = 1/2
Explanation:
Given that the spinner has 12 equal sections labelled 1-12
Let S be the sample space
Then
S = {1,2,3,4,5,6,7,8,9,10,11,12}

Let A be the event that the outcome is an even number
Then
A = {2,4,6,8,10,12}

The probability of A will be given as:

Hence,
The probability of getting an odd number when the spinner is spun, is p(even number) = 1/2