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A spinner with 12 equal sections labeled 1 -12 in spun . Find p (even number)mb

1 Answer

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Answer:

The probability of getting an odd number when the spinner is spun, is p(even number) = 1/2

Explanation:

Given that the spinner has 12 equal sections labelled 1-12

Let S be the sample space

Then

S = {1,2,3,4,5,6,7,8,9,10,11,12}


n(S) = 12

Let A be the event that the outcome is an even number

Then

A = {2,4,6,8,10,12}


n(A) = 6

The probability of A will be given as:


p(A) = (n(A))/(n(S))\\\\= (6)/(12)\\\\= (1)/(2)

Hence,

The probability of getting an odd number when the spinner is spun, is p(even number) = 1/2

User Igor Danchenko
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