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Find the 89th term of the arithmetic sequence -16, -3, 10, ...−16,−3,10,...

1 Answer

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Answer:

1128

Explanation:

hello :

this aritmetic seq when the first term is A1 =-16

the common diference is d= 10-(-3)=(-3)-(-16)=13

the nth term is : An =A1+(n-1)d =-16+13(n-1) =13n-29

the 89th term when : n=89 A89 = 13(89)-29 = 1128

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