Answer:
1. He has 23 coins in $10, and 18 coins in $20
2. He has 18 coins in $10, and 16 coins in $20
Step-by-step explanation:
The number of $10 and $20 are two variables that can only be determined simultaneously. The product of the number of each type of coin with the value of each coin gives the total amount owned.
Let the number of of $10 coins owned be x and that of $20 be y
If he has a collection of 41 coins then
x + y = 41
If the face value of the coins is $590
then,
10x + 20y = 590
solving both simultaneously
x + y = 41
x + 2y = 59
y = 59 - 41
= 18
x = 41- 18
= 23
It means he has 23 coins in $10, and 18 coins in $20.
If he has a collection of 34 coins then
x + y = 34
If the face value of the coins is $500
then,
10x + 20y = 500
solving both simultaneously
x + y = 34
x + 2y = 50
y = 50 - 34
= 16
x = 34- 16
= 18
It means he has 18 coins in $10, and 16 coins in $20