Question

Please help

A ladybug eats 200 J of plant material. Of this, 100 J is eliminated as feces and 75 J are used in cellular respiration. What is the approximate production efficiency of this animal?

A) 2.0%
B) 2.5%
C) 20%
D) 25%

Answer 1

25% is the approximate production efficiency of this animal

Step-by-step explanation:

Given ,

A ladybug eats 200 J of plant material

100 J is eliminated as feces

75 J are used in cellular respiration,

Now,

The approximate production efficiency of this animal :

200 - (100 +75) = 25 %