Answer:
Specific heat capacity of the copper is given as
![s = 0.39 J/g ^oC](https://img.qammunity.org/2021/formulas/physics/middle-school/pe07uv275yjf5gz23e539onp9p658j1nyj.png)
Step-by-step explanation:
As we know that the heat required to raise the temperature of the given substance is given as
![Q = ms\Delta T](https://img.qammunity.org/2021/formulas/physics/middle-school/mor0goiqqv9ld1z3n68luax0n5ulolcz63.png)
here we know that
![Q = 117 J](https://img.qammunity.org/2021/formulas/physics/middle-school/oiwljaxyju3l9ab85cv9q7jjpesheb485t.png)
mass of the given part is
![m = 75 g](https://img.qammunity.org/2021/formulas/physics/middle-school/kl6nok6xypf602i6cmobzleoq5cbg4ixng.png)
change in temperature due to heat supply is
![\Delta T = 24 - 20 = 4^oC](https://img.qammunity.org/2021/formulas/physics/middle-school/h5vimi153a7xyh97hnj9tybf2qmwxwyip6.png)
now we have
![117 = 75 (s)(4)](https://img.qammunity.org/2021/formulas/physics/middle-school/y0dhsojmpw3cphrvtjlo496f2234e7a5b1.png)
![s = 0.39 J/g ^oC](https://img.qammunity.org/2021/formulas/physics/middle-school/pe07uv275yjf5gz23e539onp9p658j1nyj.png)