Question

7 times a number is 8 less than the square of that number. Find the negative solution

Answer 1

x=-1

Explanation:

Let x = the number

7x =x^2 -8

Subtract 7x from each side

7x-7x = x^2 -7x -8

0 = x^2 -7x -8

Factor

0 = (x-8) (x+1)

Using the zero product property

x-8 =0 x+1 =0

x=8 x=-1

We want the negative solution x=-1