What is the pOH of a 5.6 x 10-5 M solution of cesium hydroxide (CsOH)?

asked Feb 14, 2021 69.2k views

2 votes

What is the pOH of a
5.6 x 10-5 M solution of cesium
hydroxide (CsOH)?

6.2k points

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5 votes

Answer: 4.25

Explanation: CsOH=Cs+

pOH= -log10

= -log10(5.6*10^-5)

= -log10(5.6*10^-5)=-(-4.25)

=4.25

Denis Buzmakov answered Feb 19, 2021

6.5k points

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