Answer:
The value of Discriminant is -28.
The discriminant is negative, it implies that the function has no real solution.
Explanation:
Given,
![f(x)=-4x^2+10x-8](https://img.qammunity.org/2021/formulas/mathematics/high-school/qkgqrcbf1zyt9drytn3zb39ofvc45yqslb.png)
We need to find the value of discriminant.
And also we need to find the number of real zeros 'f(x)' have.
Solution,
We have given the quadratic equation;
![f(x)=-4x^2+10x-8](https://img.qammunity.org/2021/formulas/mathematics/high-school/qkgqrcbf1zyt9drytn3zb39ofvc45yqslb.png)
where
![a = -4\\\\b = 10\\\\c = -8](https://img.qammunity.org/2021/formulas/mathematics/high-school/rxgbmha45mjvxuslp2suv6zbclkqa23jgn.png)
Now we will find the Discriminant.
Discriminant can be calculated by using the formula
.
Substituting the values we get;
![D=b^2 - 4ac = 10^2-4*(-4)*(-8)=100-128 =-28](https://img.qammunity.org/2021/formulas/mathematics/high-school/u8ypxyn29xrvp772zvndhxit54l1kr8vgd.png)
Hence the value of Discriminant is -28.
Since the discriminant is negative, it implies that the function has no real solution.