Question

If x an integer and 2x +8 <22 and 3x >9, how many possible values of x are there?

Answer 1

4, 5 and 6.

Explanation:

2x + 8 < 22

2x < 14

x < 7.

3x > 9

x > 3.

So the possible values if x is an integer are 4, 5 and 6.

Answer 2

3 values

Explanation:

2x +8 <22 and 3x >9

Solve the two inequalities separately and then put them back together

2x +8 <22

Subtract 8 from each side

2x +8-8 <22 -8

2x < 14

Divide by 2

2x/2 < 14/2

x < 7

Then solve the second inequality

3x>9

Divide by 3

3x/3>9/3

x >3

Putting them back together

x>3 and x < 7

Since it has to be an integer

4,5,6 are possible choices

3 values