What mass of H2SO4 would be required to react with 0.75 mil NaOH

Question

asked Sep 2, 2021 149k views

1 Answer

Qurben · Answer 1 · 2021-09-08T18:19:33+0000

Answer:

36.75 grams of sulfuric acid will be required.

Step-by-step explanation:

Moles of sodium hydroxide = 0.75 mol

$2NaOH+H_2SO_4\rightarrow Na_2SO_4+2H_2O$

According to reaction, 2 moles of sodium hydroxide reacts with 1 mole of sulfuric acid ,then 0.75 moles of NaOH will :

(1)/(2)* 0.75 mol=0.375 mol sulfuric acid

Mass of 0.375 moles of sulfuric acid:

0.375 mol × 98 g/mol = 36.75 g

36.75 grams of sulfuric acid will be required.