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Find the molarity of 131 g Ba(NO3)2 dissolved in 750.0 water

1 Answer

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Answer:

6.68 x 10^-4

Step-by-step explanation:

131g ÷ 261.337g/mol = 0.5012685 moles

0.5012685 moles ÷ 750.0 liters =

0.5012685÷ 750.0=0.000668358

6.68 x 10^-4

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