Question

A 2.00 L bottle of Dr Pepper contains 225 g of sucrose, C12H22O11. What is the molality of that solution?

Answer 1

Molality = 0.33 mol/Kg

Step-by-step explanation:

Given data:

Volume of solvent = 2.00 L

Mass of solute = 225 g

Molality of solution = ?

Solution:

Formula:

Molality = Number of moles of solute / kg of solvent

Now we will calculate the moles of solute.

Number of moles = mass/ molar mass

Number of moles = 225 g/ 342.3 g/mol

Number of moles = 0.66 mol

Now we will calculate the Kg of solvent.

1 L = 1 Kg

2 L = 2 Kg

Molality = Number of moles of solute / kg of solvent

Molality = 0.66 mol / 2 kg

Molality = 0.33 mol/Kg