Question

A charge of 0.05 C moves a negative charge upward due to a 2 N force exerted by an electric field. What is the

magnitude and direction of the electric field?
0.03 N upward
0.03 N downward
40 N upward
40 N downward

Answer 1

40 n/c downward on edge! :)

Step-by-step explanation:

Answer 2

Electric field at this position of charge is 40 N/C and upwards in the direction of force

Step-by-step explanation:

As we know that the force on a charge due to electric field is given as

`F = qE`

here we know that

F = 2 N

q = 0.05 C

now from above formula

`2 = (0.05) E`

here we have

`E = 40 N/C`