Answer:
1) For this case we can use the absolute value and we can write the limit with this expression:
![|T-38| \leq 2](https://img.qammunity.org/2021/formulas/mathematics/high-school/sd107bpzgrj9jxdctxzdollpv3fr86cvt9.png)
Where T represent the temperature for the refrigerator in F.
2) If we solve for T we have this:
![-2 \leq T-38 \leq 2](https://img.qammunity.org/2021/formulas/mathematics/high-school/lnyiv6lxeo6hpg7oznfjybnptvks45blh4.png)
We can add 38 in all the sides of the inequality
![-2+38 \leq T\leq 2+38](https://img.qammunity.org/2021/formulas/mathematics/high-school/62x5b4hzyrty7ze83afpaziy3yhk3ok8vd.png)
And finally we got:
![36 \leq T \leq 40](https://img.qammunity.org/2021/formulas/mathematics/high-school/61yjyfaqnj736tl7s3hxh8r9jsj70jj0bk.png)
So then the refrigerator can work between 36 F and 40 F for this case.
Explanation:
For this case we know that the refrigerator hould be set at 38 F, and the allowance or the variation is 2F.
Part 1
For this case we can use the absolute value and we can write the limit with this expression:
![|T-38| \leq 2](https://img.qammunity.org/2021/formulas/mathematics/high-school/sd107bpzgrj9jxdctxzdollpv3fr86cvt9.png)
Where T represent the temperature for the refrigerator in F.
Part 2
If we solve for T we have this:
![-2 \leq T-38 \leq 2](https://img.qammunity.org/2021/formulas/mathematics/high-school/lnyiv6lxeo6hpg7oznfjybnptvks45blh4.png)
We can add 38 in all the sides of the inequality
![-2+38 \leq T\leq 2+38](https://img.qammunity.org/2021/formulas/mathematics/high-school/62x5b4hzyrty7ze83afpaziy3yhk3ok8vd.png)
And finally we got:
![36 \leq T \leq 40](https://img.qammunity.org/2021/formulas/mathematics/high-school/61yjyfaqnj736tl7s3hxh8r9jsj70jj0bk.png)
So then the refrigerator can work between 36 F and 40 F for this case.