Question

Two tiny particles carrying like charges of the same magnitude are apart. if the electric force on one of them is what is the magnitude of the charge on each of these particles?(k = 1/4πε0 = 9.0 × 109 n • m2/c2)

Answer 1

`2.4* 10^(-8) C`

Step-by-step explanation:

We are given that

Distance between two tiny particles=d=1mm=
`1* 10^(-3) m`

Force,F=5 N

We have to find the magnitude of the charge on each of these particles.

Let charge on each particle=q

By Coulomb's law of force

`F=(kq_1q_2)/(r^2)=(kq^2)/(r^2)`

Where
`k=9* 10^9`

Substitute the values

`5=(9* 10^9q^2)/((1* 10^(-3))^2)`

`q^2=(5* (1* 10^(-3))^2)/(9* 10^9)`

`q=\sqrt{(5* (1* 10^(-3))^2)/(9* 10^9)}`

`q=2.4* 10^(-8) C`