Question

Determine the diameter, to the nearest inch, of a large can of tuna fish that has a volume of 66 inches and a height of 3.3 inches.

Answer 1

The diameter of the tuna fish is 5.048 inches, If it has a volume of 66 inches and a height of 3.3 inches.

Explanation:

The given is,

A volume of tuna fish is 66 inches

Height of tuna fish is 3.3 inches

Step:1

Let, V - Volume of the tuna fish

h - Height of tuna fish

Where,

V - 66 cubic inches

h - 3.3 inches

Step:2

Formula to calculate the area is,

Area,
`A = (Volume)/(Height)`

=
`(66)/(3.3)`

A = 20 square inches

Step:3

Formula to calculate the radius,

Radius,
`r^(2) = (A)/(\pi )`

`r^(2)` =
`(20)/(3.14)`

r =
`√(6.36943)`

r = 2.524 inches

Step:4

Formula to calculate the diameter,

`d=2r`

= 2 × 2.524

d = 5.048 inches

Result:

Thus the diameter of the tuna fish is 5.048 inches, If it has a volume of 66 inches and a height of 3.3 inches.