Answer:
The age is 106
Explanation:
The hints are:
HINT 1
If you take my age and divide it by any odd number greater than 1 and less than 9, you will get a remainder of 1.
Let the age be A
There odd numbers between 1 and 9 are: 3, 5 and 7.
Then
A/3 = B remainder 1
A/5 = C remainder 1
A/7 = D remainder 1.
HINT 2
If you take my age and divide it by any even number greater than 1 and less than 9, you will not get a remainder of 1.
The even number between 1 and 9 are: 2, 4, 6 and 8.
A/2 = P remainder l
A/4 = Q remainder m
A/6 = R remainder n
A/8 = S remainder o
Where l ≠ 1, m ≠ 1, n ≠ 1, and o ≠ 1.
From the first hint, notice that 3, 5, and 7 would have been factors of his age, if not for the remainder 1. It will make sense to say the number after 3, 5 and 7 are factors of the number before his age.
Example: 3 and 5 are factors of 3×5 = 15 right?
Add 1 to 15, we have 16.
16/3 = 5 remainder 1
16/5 = 3 remainder 1.
So, 5 and 3 are factors of the number before 16.
Now, back to our work
3, 5, and 7 are factors of 3×5×7 = 105
Dividing 105 by 3 or 5 or 7 give a number without remainder.
Now dividing 105 + 1 = 106, by any of these number will give a remainder of 1.
The second hint, dividing 106 by any of 2, 4, 6, and 8 will not give a remainder of 1.
Then the age is 106