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A hemispherical tank is filled with water and has a diameter of 4 feet. If water weighs 62.4 pounds per cubic foot, what is the total weight of the water in a full tank, to the nearest pound?

1 Answer

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The total weight of the water in a full tank, to the nearest pound is 1056 pounds, if water filled with water in the 4 diameter hemispherical tank and weighs 62.4 pounds per cubic foot.

Explanation:

The given is,

A hemispherical tank is filled with water and has a diameter of 4 feet.

Water weighs 62.4 pounds per cubic foot

Step:1

Formula to weight of water is,

= Volume of water tank × weight of water per foot......(1)

Step:2

Formula to find volume of the tank is,


V = (2)/(3) \pi r^(3)...................................(2)

From given, r = Radius of Hemisphere


r = (d)/(2)


= (4)/(2)

r = 2 foot

From equation (2),

=
(2)/(3) ×
\pi ×
2^(3)

= 16.755 cubic foot

Step:3

From equation (1),

= 16.775 × 62.4 (∵ Water weighs 62.4 pounds per cubic foot )

= 1045.52 pounds ( ∵
foot^(3) ×
(pounds)/(foot^(3)) =
pounds )

≅ 1046 pounds

Weight of water in tank = 1046 pounds

Result:

The total weight of the water in a full tank, to the nearest pound is 1056 pounds, if a hemispherical tank is filled with water and it has 4 feet diameter and water weighs 62.4 pounds per cubic foot.

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