Question

​claim: the mean pulse rate​ (in beats per​ minute) of adult males is equal to 6969 bpm. for a random sample of 125125 adult​ males, the mean pulse rate is 69.269.2 bpm and the standard deviation is 10.910.9 bpm. find the value of the test statistic. the value of the test statistic is nothing. ​(round to two decimal places as​ needed.)

Answer 1

t=0.21

Explanation:

Given
`\bar x=69.2, s=10.9, n=125`and a population mean
`\mu=69`.

#We state our hypothesis as:

`H_o:\mu=69\\\\H_a:\mu\\eq 69`

The evidence available should validate either the null or alternative hypothesis.

#We calculate the test statistic as:

`t=(\bar x-\mu_)/(s/√(n))\\\\\\=(69.2-69)/(10.9/√(125))\\\\\\=0.2051`

`\approx0.21`

Hence, the test statistic is t=0.21