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Find the relative minimum of y = 2x 3 + 14x 2 - 10x - 46

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6 votes

Answer:

The minimum value is 47.704 when x = 1/3 correct to the nearest thousandth.

Explanation:

y = 2x^3 + 14x^2 - 10x - 46

To find the turning point(s) on the curve we first differentiate:

dy/dx = 6x^2 + 28x - 10 This = zero for turning points:

6x^2 + 28x - 10 = 0

2(3x^2 + 14x - 5) = 0

(3x - 1 )(x + 5) = 0

x= 1/3, - 5.

We now determine the nature of the turning points:

The second derivative is 12x + 28

When x = 1/3 it's value is positive.

When x = -5 its value is -60 + 28 which is negative.

So x = 1/3 gives a relative minimum.

When x = 1/3, y = -47.704.

User AssamGuy
by
7.7k points
2 votes
The answer is x= 23/12 OR x=1 11/12 OR x=1.916
User Burnall
by
8.1k points

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