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500mL of He at 98 kPa expands to 750 mL. Find P2

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The value of P₂ is 65.33 kPa

Step-by-step explanation:

Given:

Volume, V₁ = 500mL

Pressure, P₁ = 98 kPa

Volume, V₂ = 750 mL

Pressure, P₂ = ?

According to Boyle's law:

P₁V₁ = P₂V₂

On substituting the value we get:


98 X 500 = 750 X P_2\\\\P_2 = (98 X 500)/(750) \\\\P_2 = 65.33 kPa

The value of P₂ is 65.33 kPa

User Tim Taurit
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