Question

A big box of sausages (30 kg) is lifted from the ground to the top shelf of the freezer. If the box is lifted at a constant speed, a distance of 1.75 m, what work is done against gravity?

Answer 1

Work done to lift the box is 515.03 J

Step-by-step explanation:

By work energy theorem we know that work done by all forces is equal to change in kinetic energy

So we have

`W_g + W_(ex) = \Delta K`

so we have

`-mgh + W_(ex) = 0`

so we have

`W_(ex) = mgh`

`W_(ex) = 30(9.8)1.75`

`W_(ex) = 515.03 J`