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How many formula units of silver fluoride, AgF, are equal to 42.15 g f this substance?

User Yname
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1 Answer

2 votes

Answer:

1.99 x 10²³ formula units

Step-by-step explanation:

Given parameters:

Mass of AgF = 42.15g

Unknown:

The amount of formula units

Solution:

To solve this problem, we set out by find the number of moles in this compound from the given mass.

Number of moles =
(mass)/(molar mass)

molar mass of AgF = 107.9 + 19 = 126.9g/mol

Number of moles =
(42.15)/(126.9) = 0.33 moles

1 mole of a substance = 6.02 x 10²³ formula units

0.33 moles of AgF = 0.33 x 6.02 x 10²³ = 1.99 x 10²³ formula units

User Ultifinitus
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