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How many formula units of silver fluoride, AgF, are equal to 42.15 g of this substance?

User YasBES
by
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2 Answers

5 votes

Answer:

2.00 × 10²³ formula units

Step-by-step explanation:

Given data:

Mass of AgF = 42.15 g

Number of formula units = ?

Solution:

Number of moles of AgF:

Number of moles = mass/ molar mass

Number of moles = 42.15 g/ 126.87 g/mol

Number of moles = 0.34 mol

Now Number of formula units will be determine by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number

1 mole = 6.022 × 10²³ formula units

0.34 mol × 6.022 × 10²³ formula units

2.00 × 10²³ formula units

User Frankusky
by
6.2k points
4 votes

Answer:

2.05 × 10²³ formula units

Step-by-step explanation:

Given data:

Mass of AgF = 43.15 g

Number of formula units = ?

Solution:

Number of moles of AgF:

Number of moles = mass/ molar mass

Number of moles = 43.15 g/ 126.87 g/mol

Number of moles = 0.34 mol

Now Number of formula units will be determine by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number

1 mole = 6.022 × 10²³ formula units

0.34 mol × 6.022 × 10²³ formula units

2.05 × 10²³ formula units

User Fantastic Mr Fox
by
6.1k points