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4 votes
Factor: x2 + 12x + 35 *
O (x+5)(x+7)
(x+7)(x-5)
O (x+4)(x+3)
O Prime

User Karley
by
8.1k points

2 Answers

5 votes


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x {}^(2) + 12x + 35


x {}^(2) + 7x + 5x + 35


x(x + 7) + 5(x + 7)


(x + 5)(x + 7)

User Lovlesh
by
8.4k points
3 votes

Answer:

(x+5)(x+7)

Explanation:

We need to find two binomials of the form (x+a) and (x+b) such that their product gives
x^2+12x+35

So, notice that the values for "a" and for "b" in the binomials to factor should verify that :

1) a * b = 35

and 2) a+b = 12

Since the product (x+a) times (x+b) =
x^2+ax+bx+a*b= x^2+(a+b)x +a*b

The pair of values 7 and 5 satisfy such conditions.

Therefore (x+5) (x+7) =
x^2+12x+35

and then (x+5) and (x+7) are binomial factors of the original trinomial.

User FtLie
by
8.3k points

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