Question

What is the force between two negatively charged objects if q1 = 2.5x10^-6 C, q2 = 4.3x10-6 C and the distance between the charges is 0.04m

Answer 1

The force between the charges is 60.47N

Step-by-step explanation:

Given:

Charge, q₁ = 2.5 X 10⁻⁶ C

q₂ = 4.3 X 10⁻⁶ C

Distance, r = 0.04m

Force, F = ?

According to Coulomb's law:

`F = k(q_1q_2)/(r^2)`

where,

k = Coulomb's constant

and the value of k is 9 X 10⁹ Nm²/C²

On substituting the value we get:

`F = 9 X 10^9X(2.5 X 10^-^6 X 4.3 X 10^-^6)/((0.04)^2) \\\\F = 60.47N`

Therefore, the force between the charges is 60.47N