For this case we have that by definition, the perimeter of a recatangle is given by:
![P = 2b + 2h](https://img.qammunity.org/2021/formulas/mathematics/middle-school/vqbgcz6tnni76leugtw9zptstvamybahj9.png)
Where:
b: It is the base of the rectangle
h: Is the height of the rectangle
According to the data of the statement we have:
![P = 20 \ cm\\b = \frac {2} {3} h](https://img.qammunity.org/2021/formulas/mathematics/middle-school/oenktil6dmt62xzwfisn2nergdtzoajdr1.png)
Substituting we have:
![20 = 2 \frac {2} {3} h + 2h\\20 = \frac {4} {3} h + 2h\\20 = \frac {10} {3} h\\60 = 10h\\h = \frac {60} {10}\\h = 6](https://img.qammunity.org/2021/formulas/mathematics/middle-school/5uxklznnxbqf3q5lzk4kt6z9acmjpi7scx.png)
Thus, the height of the rectangle is
![6 \ cm](https://img.qammunity.org/2021/formulas/mathematics/middle-school/3i3iafcrmh4po85h15w8nczqe8ij46a00h.png)
![b = \frac {2} {3} (6) = 4 \ cm](https://img.qammunity.org/2021/formulas/mathematics/middle-school/m8biuvqa6ncy6o7ik6a9f77a7tcggiq04h.png)
So the area is:
![A = b * h\\A = 4 * 6\\A = 24 \ cm ^ 2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/wx9vt02zxejr0lz7rs4hw2k9awpn4bgu82.png)
Answer:
![24 \ cm ^ 2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/7oiw0muv7javii5ef0csc8vjfuanzqjkf2.png)