Question

Solve the system of equations x – 2y = -19 and - 3x + 5y = 48 by combining
the equations.

Answer 1

x=−1 and y=9

Explanation:

Multiply the first equation by 3,and multiply the second equation by 1.

3(x−2y=−19)

1(−3x+5y=48)

Becomes:

3x−6y=−57

−3x+5y=48

Add these equations to eliminate x:

−y=−9

Then solve−y=−9for y:

−y=−9

(divide both sides by -1)

y=9

Now that we've found y let's plug it back in to solve for x.

Write down an original equation:

x−2y=−19

Substitute 9 for y in x−2y=−19:

x−(2)(9)=−19

x−18=−19(Simplify both sides of the equation)

x−18+18=−19+18(Add 18 to both sides)

x=−1

Answer 2

x= -1

y = 9

Explanation:

to solve this system of equation

let

x - 2y = -19.....................................equation 1

-3x + 5y = 48 .................................. equation2

from equation 1

x - 2y = -19.....................................equation 1

x = -19 + 2y................................... equation 3

substitute the value of x into equation 2

-3x + 5y = 48 .................................. equation2

-3(-19 + 2y) + 5y = 48

57 - 6y + 5y = 48

combine the like terms

-6y + 5y = 48 -57

-y = - 9

divide both side by -

y = 9

put y= 9 into equation 3

x = -19 + 2y................................... equation 3

x = -19 + 2(9)

x = -19 + 18

x = -1

therefore the value of x and y is -1 and 9 respectively