Answer:
x = -1
y = 0
Explanation:
to solve the equation by substitution in order to evaluate for x and y
let
6x-2y=-6 ................................................ equation 1
-2x-3y=2 .................................................. equation2
from equation 2
-2x-3y=2 .................................................. equation2
-2x -2 = 3y
divide both sides by 3
(-2x -2)/3 = y
y = (-2x -2)/3 ................................... equation3
substitute y = (-2x -2)/3 into equation 1
6x-2y=-6 ................................................ equation 1
6x - 2[ (-2x -2)/3] = -6
6x + (4x + 4)/ 3 = -6
multiply through by 3
18x + 4x + 4 = -18
22x = -18-4
22x = -22
divide both sides by the coefficient of x which is 22
22x/22 = -22/22
x = -1
substitute for x in equation 3
y = (-2x -2)/3 ................................... equation3
y = -2(-1) - 2/3
y = 2 -2/3
y = 0/3
y = 0
therefore the value of x and y is -1 and 0 respectively