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What is the vertex of the graph of y=x^2+4x

User Jamiedanq
by
7.5k points

1 Answer

3 votes

Answer:

Vertex is at

( 2 , − 4 )

Explanation:

x v e r t e x = − b 2 a ; y v e r t e x = f ( − b 2 a ) given the equation in the standard form of

a x 2 + b x + c

Given : y = x 2 − 4 x + 0a = 1 , b = − 4 , c = 0

x v e r t e x = − ( − 4 ) 2 ⋅ 1 =4 2 = 2

y v e r t e x = f ( 2 ) = ( 2 ) 2 − 4 ( 2 ) = 4 − 8 = − 4

Vertex : ( x , y ) = ( 2 , − 4 )

graph{x^2-4x [-6.43, 7.62, -5.635, 1.39]}

User Jeff Victorino
by
8.0k points

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