Answer:
![\displaystyle A=( 4 )/( x^(14) y^(8))](https://img.qammunity.org/2021/formulas/mathematics/college/pfee700llzwpnj34e4cgfnli1pkru9v8di.png)
Explanation:
Properties of Powers
The algebraic expression called power has the form x^y where x is called the base and y is called the exponent.
Powers have some properties, some of which we'll recall below
![(x^a)^b=x^(ab)](https://img.qammunity.org/2021/formulas/mathematics/college/3thh23tueyq6cutfmss19alu2tkfk3rxx8.png)
![(x^a)(x^b)=x^(a+b)](https://img.qammunity.org/2021/formulas/mathematics/college/odoi9r33jqt0zwoqf17ixu9sp5qdywfy5n.png)
![\displaystyle (x^a)/(x^b)=x^(a-b)](https://img.qammunity.org/2021/formulas/mathematics/college/8pzc3oyj24wr9nlsibv294uprzj0zwfeal.png)
![\displaystyle x^(-a)=(1)/(x^a)](https://img.qammunity.org/2021/formulas/mathematics/college/67zgnmsr8vvdtrv1evk68e8gmduejz4d21.png)
![\displaystyle x^(a)=(1)/(x^(-a))](https://img.qammunity.org/2021/formulas/mathematics/college/p1zvuhzn38vrm3et40uapzs896l4jbplnw.png)
We'll use those properties to simplify the expression
![\displaystyle A=\left( ( (2)^(-3)(x^(-3)) (y^2) )/((4^(-2)) (x^4) (y^6)) \right)^2](https://img.qammunity.org/2021/formulas/mathematics/college/4201u38utwp9ug5pj04l8a8e1r84evhm3n.png)
Taking the power 2 of every term
![\displaystyle A=( (2)^(-6)(x^(-6)) (y^4) )/((4^(-4)) (x^8) (y^(12)))](https://img.qammunity.org/2021/formulas/mathematics/college/5zzqjixlrfngcrw1bwhqqsid9ecpcof4sm.png)
Moving the terms with negative exponent to its opposite side
![\displaystyle A=( (2)^(-6) (4^(4))(y^4) )/( (x^8)(x^(6)) (y^(12)))](https://img.qammunity.org/2021/formulas/mathematics/college/1s8tuozrskrk84i9u9mg3kf9r7rgrklv5z.png)
Operating the explicit same bases
![\displaystyle A=( (2)^(-6) (4^(4)) )/( (x^(14)) (y^(12-4)))](https://img.qammunity.org/2021/formulas/mathematics/college/awd8bjalwbmwupx4nyvfaqvelc955e1lp0.png)
Since
![4^4=(2^2)^4=2^8](https://img.qammunity.org/2021/formulas/mathematics/college/ll0b5fj3ylr3x5fcg0wcyi6nvn3luk0xzo.png)
![\displaystyle A=( (2)^(-6) (2^8) )/( (x^(14)) (y^(12-4)))](https://img.qammunity.org/2021/formulas/mathematics/college/zsc3ywv9rsksh3jq1lbt5nfsaidbpc4gdx.png)
Operating the remaining like bases subtractions
![\displaystyle A=( (2^2) )/( (x^(14)) (y^(8)))](https://img.qammunity.org/2021/formulas/mathematics/college/xirtqog133927uza8mklg3qxtxleuertzx.png)
Finally
![\displaystyle A=( 4 )/( x^(14) y^(8))](https://img.qammunity.org/2021/formulas/mathematics/college/pfee700llzwpnj34e4cgfnli1pkru9v8di.png)