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If y=3/8x-1 find the find the equations that are perpendicular and parallel to this line that passes through (8, -2)

1 Answer

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Answer:

Explanation:

perp. -8/3

y + 2 = -8/3(x - 8)

y + 2 = -8/3x + 64/3

y + 6/3 = -8/3x + 64/3

y = -8/3x + 58/3

y + 2 = -3/8(x - 8)

y + 2 = -3/8x + 3

y = -3/8x + 1

User Alexander Duchene
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