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Quadrilateral WXYZ has interior angles that meet the following criteria:

Angles W and X are congruent.
• The smallest angle's measure is 100° less than twice the measure of W.
• The largest angle's measure is 10º more than twice the measure of 2X.
Find the measure of the smallest angle in the quadrilateral.

1 Answer

7 votes

Smallest angle is
50°

Explanation:

Here we have , Quadrilateral WXYZ has interior angles that meet the following criteria:

Angles W and X are congruent.

According to question , angles are congruent i.e. Both angle measure same


X=W

Now ,

The smallest angle's measure is 100° less than twice the measure of W.

According to above statement we have ,

Smallest angle =
2W-100

• The largest angle's measure is 10º more than twice the measure of X. ( correction , in question given as 2X )

According to above statement we have ,

Largest angle =
10+2X=10+2X

Now , We know that sum of all 4 angles in 360 i.e.


X+W+10+2X+2W-100=360 { X=W }


6W-90=360


6W=450


W=75

Smallest angle is :
2W-100 = 2(75)-100=50

Therefore , Smallest angle is
50° .

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