Question

Solve general solutions

`√(3tan \:) (2x - 10) + 1 = 0`
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Answer 1

`\\ \rm\Rrightarrow √(3tan(2x-10))+1=0`

`\\ \rm\Rrightarrow √(3tan(2x-10))=-1`

`\\ \rm\Rrightarrow 3tan(2x+10)=1`

`\\ \rm\Rrightarrow tan(2x+10)=1/3`

• 1/3=0.33..
• tan^{-1}(0.33)≈18

`\\ \rm\Rrightarrow 2x+10=18`

`\\ \rm\Rrightarrow 2x=8`

`\\ \rm\Rrightarrow x=4`