Answer:
here 20 lb object will hit the ground first
Step-by-step explanation:
Acceleration of the object while it is dropped in air is given as
![F = mg](https://img.qammunity.org/2021/formulas/physics/college/9cmjuq974npiy9qds95raooh31ifm8o93o.png)
![a = (F)/(m)](https://img.qammunity.org/2021/formulas/physics/college/hvv27u7axcvpa6drx29d2al07tpn90ewfm.png)
![a = g](https://img.qammunity.org/2021/formulas/physics/middle-school/x2amboiknuj2kacq8mibgpbr70un2me5sl.png)
so acceleration of the object is independent of the mass of the object
now time to reach the ground is given as
![h = (1)/(2)gt^2](https://img.qammunity.org/2021/formulas/physics/middle-school/h29ch3x2nnp5wodml3y5kp14n08ir9ah7f.png)
![t = \sqrt{(2h)/(g)}](https://img.qammunity.org/2021/formulas/physics/college/6vn5md75ndzxksyrsyz4szf8scu1o80r6a.png)
for 20 pound object
![t_1 = \sqrt{(2(50))/(32)}](https://img.qammunity.org/2021/formulas/physics/middle-school/eauep2mkunwngs0pfc3h57gf5h1zh2857w.png)
![t_1 = 1.77 s](https://img.qammunity.org/2021/formulas/physics/middle-school/ikdezvf4ap7cjxau3wprnp6jlxq1w1hgul.png)
for 50 pound object
![t_2 = \sqrt{(2(100))/(32)}](https://img.qammunity.org/2021/formulas/physics/middle-school/39nggr5kbi3g1edjtyy6qrfzmg2412gtsc.png)
![t_2 = 2.5 s](https://img.qammunity.org/2021/formulas/physics/middle-school/1w1rbr8vva1l3n2ezmegndvgnha8cw5qer.png)