Answer:
f (x) = x2:g(x) =
–x2 – 4x + 5:
h(x) = x2 – 3x – 4:
k(x) = (x + 4)2
y = x2 + 3
x2 + 3.
Given g(x) = 4x – 3
g(x) – 2 = (4x – 3) – 2
= 4x – 5
h(x) = 4x – 5
Given f (x) = –x2 + 5x + 2,
f (x + 5)
w(t) = s(t – 1)
= 2(t – 1) + 4
= 2t – 2 + 4
= 2t + 2
w(t) = 2t + 2
Explanation: