Answer:
Step-by-step explanation:
i) mean number of defective bulbs per case
ii) Ha : μ > 20
From the given output:
iii) 1.3006
iv) Null hypothesis is rejected because p-value = 0.021 < 0.10.
v) risk of committing of a type1 error is alpha = 0.10.
vi) Yes, there is sufficient evidence that the mean number of defective bulbs per case is greater than 20 during the morning shift.
vii) The manager can conclude that the mean number of defective bulbs per case during the morning shift is greater than 20 using a level of significance of 0.10.
viii) for two tailed test, p-value would be double.
p-value=2(0.021)={\color{Red} 0.042}