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What is the wavelength of the third harmonic in a 4.5-m-long pipe that is closed at one end?

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Answer:

Wavelength of sound in the pipe is 6.0 m

Step-by-step explanation:

As we know that closed pipe is given to us so here at open end it will form antinode while at closed end it will form Node

Here we know that in closed pipes on odd harmonics will exist

so here for third harmonic we have


L = (\lambda)/(4) + (\lambda)/(2)

where L = length of the pipe

so we have


4.5 = (3\lambda)/(4)


\lambda = 6.0 m

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