Answer:
126 groups
Explanation:
we know that
This is a combination problem, because the order doesn't matter. He has 9 toys and wants to know the number of different combinations of 5 he can take.
The formula for the number of possible combinations of r objects from a set of n objects is given by
![^nC_r=\frac{ {n!}}{r!(n-r)!}](https://img.qammunity.org/2021/formulas/mathematics/middle-school/oz4b74z82jzuxgh7rvrsn4h18l2ntf27hx.png)
In this problem we have
![n=9, r=5](https://img.qammunity.org/2021/formulas/mathematics/middle-school/82cwgml738v9mo8893svtrj2op6anatqxn.png)
substitute
![^9C_5=\frac{ {9!}}{5!(9-5)!}](https://img.qammunity.org/2021/formulas/mathematics/middle-school/bfegmwvejdqg2ost7skbqirv1pd7l706w5.png)
![^9C_5=\frac{ {9!}}{5!(4)!}](https://img.qammunity.org/2021/formulas/mathematics/middle-school/u8gm8msto6d00c90re3vhfmhwgow7mlwe0.png)
![^9C_5=\frac{ {(9)(8)(7)(6)5!}}{5!(4)!}](https://img.qammunity.org/2021/formulas/mathematics/middle-school/to5qtmcsaq062a4j99d0icx4t0hem08v2h.png)
![^9C_5=\frac{ {9)(8)(7)(6)}}{(4*3*2*1)}](https://img.qammunity.org/2021/formulas/mathematics/middle-school/39xsttsl7rf0r8i10yd40htgruw738pwt9.png)
![^9C_5=126](https://img.qammunity.org/2021/formulas/mathematics/middle-school/md53u5byx9jrjt0q2kreddgi35aczweiof.png)