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Where does g(x) = x^2 – 10x + 24 touch the x-axis

1 Answer

4 votes

Answer:

It touches at (6, 0) and (4, 0)

Explanation:

Step 1: Factor out the expression


g(x) = x^2-10x+24


g(x) = x^2 - 6x - 4x + 24


g(x) = (x - 6)(x - 4)

Step 2: Solve for x


x - 6 + 6 = 0 + 6


x = 6


x - 4 + 4 = 0 + 4


x = 4

Answer: It touches at (6, 0) and (4, 0)

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