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The math club is electing new officers. There are 3 candidates for president, 4 candidates for vice-president, 4 candidates for secretary, and 2 candidates for treasurer. How many different combinations
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The math club is electing new officers. There are 3 candidates for president, 4 candidates for vice-president, 4 candidates for secretary, and 2 candidates for treasurer. How many different combinations of officers are possible?

User Candieduniverse
by
3.9k points

1 Answer

0 votes

Answer:

96

Explanation:

3x4=12

12x4=48

48x2=96

User Aaron Franke
by
4.0k points
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