Question

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Answer 1

`\hookrightarrow \: u = 3 || \: a = - 12 \: || t = (1)/(3) \\ \hookrightarrow \: s = ut + (1)/(2) a {t}^(2) \\ \hookrightarrow \: s =3 * (1)/(3) + (1)/(2) * - 12 * ((1)/(3) )^(2) \\ \hookrightarrow \: s =1 - (2)/(3) \\ \hookrightarrow \: s = (1)/(3)`

Answer 2

s =
`(1)/(3)`

Explanation:

s = ut +
`(1)/(2)` at² ( substitute the given values into the equation )

s = ( 3 ×
`(1)/(3)` ) + (
`(1)/(2)` × - 12 × (
`(1)/(3)` )² )

= 1 + (- 6 ×
`(1)/(9)` )

= 1 + ( -
`(2)/(3)` )

= 1 -
`(2)/(3)`

=
`(1)/(3)`