Question

) A class consists of 66 women and 98 men. if 2 students are selected what is the probability they will both be male?

Answer 1

Answer: 0.3556 or 35.56%

Explanation:

the probability of picking a male the first time is
`(num males)/(total)`

num males = 98

total = 98 + 66 = 164

so the probability the first time is
`(98)/(164)`

the probability the second time is
`(num males)/(total)`

since you already picked a male the first time, num males and total decrease by 1

num males = 98 -1 = 97

total = 164 - 1 = 163

probability the second time is
`(97)/(163)`

now multiply the probabilities of both times to get the final probability

`(98)/(164)`*
`(97)/(163)`=
`(4753)/(13366) =0.3556=35.56%`%

Answer 2

98/164 or 0.60

Explanation:

p( picking 2 males)

66 females+98 males= 164

=98/164

98 divided by 164= 0.59756097561

0.59756097561= 0.60

( thank me)