Answer:
The length of the radius of the circle is 7 mm
Explanation:
see the attached figure to better understand the problem
we know that
If HK is tangent to circle O at point K
then
The radius OK is perpendicular to segment HK and triangle OKH is a right triangle
Applying the Pythagorean Theorem
![OH^2=OK^2+HK^2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/70r1ltito7gr0dso3moapngz5pli02mxwp.png)
we have
![OH=(r+18)\ mm\\OK=r\ mm\\HK=24\ mm](https://img.qammunity.org/2021/formulas/mathematics/middle-school/bcv4jbebe5jhcjx6kpt5ywvt8riyzc2s98.png)
substitute
![(r+18)^2=r^2+24^2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/ceshs0o9iyit9qshrb5do8qj1dppynkug7.png)
solve for r
![r^2+36r+324=r^2+576](https://img.qammunity.org/2021/formulas/mathematics/middle-school/p1tsfobj7rl1gu8j8lm119upaez6y2n9wx.png)
![36r=576-324\\36r=252\\r=7\ mm](https://img.qammunity.org/2021/formulas/mathematics/middle-school/4us5kv1gpi5nqnqzdi19iczpotg87v0myk.png)
therefore
The length of the radius of the circle is 7 mm