Answer:
Write an equation for the nth term of the geometric sequences-3,6,-12,....
an= ar∩-1
a= first term
r= common ratio
an= nth term
an= -3 x (-2) (-12-1)
an= -3 x (-2) (-13)
an= -3 x (-2)(-2)(-2)(-2)(-2)(-2)(-2)(-2)(-2)(-2)(-2)(-2)(-2)(-2)
an= -3 x -16384
nth term= 49152
Explanation: