Answer:
Total Surface area of the figure =
Explanation:
The figure consists of three rectangular faces and two triangular faces :
Area of the figure = Area of the two triangular faces + Area of the three rectangular faces
Area of the two triangular faces:
![2((1)/(2) * Base * Height)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/9u9yey0bn0ym6h85enjxyn37q6hyy7mo5x.png)
![Base= 12\, cm\\Height=10\,cm](https://img.qammunity.org/2021/formulas/mathematics/middle-school/8idug1o0z9romsqoixy995bl898e74421o.png)
Area of the two triangular faces is:
![=2((1)/(2) * 12 * 10)\\\\=2((1)/(2) * 120 )\\\\=120\,cm^2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/f9xurxfwhlfl6fs0cbw0wu0vrmvcfo9rfz.png)
Area of the rectangle=
![Length* Width](https://img.qammunity.org/2021/formulas/mathematics/middle-school/6xu2kep12a9byn24bjddgutsmrcpudq3li.png)
Area of the Rectangular face with :
![Length= 11\,cm\\Width=12\,cm](https://img.qammunity.org/2021/formulas/mathematics/middle-school/c00fxgbbb0u5ixow4nexohubyj3fgpquzb.png)
Area is:
![=11* 12\\\\=132\,cm^2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/adv6qoqkkzxe9fq2eqw2gi0yd90c30wr4k.png)
Area of the rectangular face with:
![Length=15.6\,cm\\Width=11\,cm](https://img.qammunity.org/2021/formulas/mathematics/middle-school/az7wn4fz2090dvlq2gwh4aibjl39o9y46k.png)
Area is:
![=15.6* 11\\=171.6\,cm^2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/5662540jymjiw8xf5ua8ho0bb999vxj9k5.png)
For,
Area is:
![=11* 10\\=110\,cm^2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/pbz5o9022smkfh61bf0eptbpqdzla2as85.png)
Total Surface area of the figure is:
![=120+132+171.6+110\\=533.6\,cm^2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/ifabrbilonzzunibogytn1jzxg4bo2nb03.png)