Question

How many grams HBr will be produced from 0.100 moles bromine reacted with excess hydrogen?

Answer 1

Answer: 16.2

Explanation: Two moles of HBr are produced for every mole of Br2 reacting. So 0.1 moles Br2 → 0.2 moles HBr. To find the mass of HBr represented by 0.2 moles, multiply the gram formula mass of HBr by 0.2 (or divide it by 5.0, which is the same operation). The mass of HBr = 1 + 79.9 = 80.9 g / mole. 80.9 g/mole X 0.2 mole = 16.2 g HBr.

Answer 2

16.18 g HBr

Step-by-step explanation:

We are given;

0.100 moles of Bromine

We need to determine the amount of HBr produced when bromine reacts with hydrogen;

First, we write the equation for the reaction;

H₂(g) + Br₂(l) → 2HBr

From the equation;

1 mole of bromine reacts with hydrogen to form 2 moles of HBr

Therefore;

Moles of HBr = 2 × moles of Bromine

= 2 × 0.100 moles

= 0.200 moles

Secondly, we determine the mass of HBr produced

Mass = Number of moles × molar mass

Molar mass of HBr = 80.91 g/mol

Thus;

Mass of HBr = 0.200 moles × 80.91 g/mol

= 16.182 g

= 16.18 g

Therefore, the mass of HBr is 16.18 g